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31 December, 12:20

If you produced 76.10 grams of potassium chloride in the reaction how many grams of potassium were required?

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  1. 31 December, 15:28
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    Answer:39.8375

    Explanation:

    The mole for the equation is 1:1

    Then the molar mass of KCl is 74.5g

    Molar mass of k is 39

    74.5g of KCl gives 39g of k

    76.10g of KCl gives xg of k

    X = 76.10*39/74.5

    X = 2967.9/7

    X = 39.8375
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