A group of students perform three trials in a lab and determine the density of aluminum to be 2.1, 2.12, and 2.09 g/cm³ if the true density of aluminum is 2.7 g/cm³ what is the percent error of their lab

Percent error = - 22%

Explanation:

Given dа ta:

Density of aluminium = 2.1,2.12 and 2.09 g/cm³

Accepted value of density of aluminium = 2.7 g. cm³

Percent error = ?

Solution:

First of all we will calculate the average of data measured by students.

Average value = 2.1 g/cm³ + 2.12 g/cm³ + 2.09 g/cm³ / 3

Average value = 6.31 g/cm³ / 3

Average value = 2.1 g/cm³

Now we will calculate the percent error.

Percent error = [ Measured value - accepted value / accepted value ] * 100

Percent error = [ 2.1 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ] * 100

Percent error = [-0.6/2.70 g/cm³ ] * 100

Percent error = - 0.22 * 100

Percent error = - 22%