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14 November, 17:56

How many grams of sulfur (S8S8) must be dissolved in 100.0 g naphthalene (C10H8C10H8) to make a 0.11 mm solution

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  1. 14 November, 18:53
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    5.64x10⁻³ g of S₈S₈

    Explanation:

    We consider mm as milimolal

    Milimolal = molal. 1000

    Molal are the moles of solute contained in 1kg of solvent.

    Solute → Sulfur (S₈S₈)

    Solvent → naphthalene

    0.11 mm / 1000 = 1.1x10⁻⁴ molal

    moles of solute / kg of solvent = 1.1x10⁻⁴ molal

    moles of solute / 0.1 kg of solvent = 1.1x10⁻⁴ molal

    moles of solute = 1.1x10⁻⁴ m/kg. 0.1kg → 1.1ₓ10⁻⁵ moles

    Molar mass S₈S₈ = 512.96 g/m

    1.1ₓ10⁻⁵ mol. 512.96 g/m = 5.64x10⁻³ g
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