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19 April, 00:46

A gas mixture contains 0.150 mol of oxygen (O2) gas and 0.211 mol of argon (Ar) gas. The total pressure of the mixture is 159 kPa. What is the partial pressure of Ar in the mixture? Report your answer with the correct number of significant figures.

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  1. 19 April, 03:23
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    The partial pressure of argon is 92.9 kPa (or 0.917 atm)

    Explanation:

    Step 1: Data given

    Moles of O2 = 0.150 mol

    Moles of argon = 0.211 mol

    Total pressure = 159 kPa

    Step 2: Calculate mole fraction of Ar

    Mole fraction Ar = 0.211 / (0.211+0.150)

    Mole fraction Ar = 0.584

    Step 3: Calculate the partial pressure

    Partial pressure of argon = Mole fraction * Total pressure

    Partial pressure argon = 0.584 * 159 kPa

    Partial pressure argon = 92.9 kPa ( = 0.917 atm)

    The partial pressure of argon is 92.9 kPa (or 0.917 atm)
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