How much energy must be removed from a 125 g sample of benzene (molar mass = 78.11 g/mol) at 425.0 K to liquify the sample and lower the temperature to 335.0 K? The following physical data may be useful. Hvap = 33.9 kJ/molHfus = 9.8 kJ/molCliq = 1.73 J/g CCgas = 1.06 J/g CCsol = 1.51 J/g CTmelting = 279.0 KTboiling = 353.0 Ka. 95.4 kJ

b. 74.4 kJ

c. 38.9 kJ

d. 67.7 kJ

e. 54.3 kJ

Question

Chemistry

Nikolas

9 June, 11:34

How much energy must be removed from a 125 g sample of benzene (molar mass = 78.11 g/mol) at 425.0 K to liquify the sample and lower the temperature to 335.0 K? The following physical data may be useful. Hvap = 33.9 kJ/molHfus = 9.8 kJ/molCliq = 1.73 J/g CCgas = 1.06 J/g CCsol = 1.51 J/g CTmelting = 279.0 KTboiling = 353.0 Ka. 95.4 kJ

b. 74.4 kJ

c. 38.9 kJ

d. 67.7 kJ

e. 54.3 kJ

+2

Answers (1)

Know the Answer?

Liam Knox · Answer 1

Answer: d) 67.7KJ

Explanation:

Number of moles of Benzene = 125/78.11=1.60 moles

Q = mc◇T = 125 * 1.60 * (425-353) = 9540J

Q = ◇Hvap * 1.60=

33.9 * 1.60 = 54.24KJ

Q = mc◇T = 125 * 1.73 * (353-335) = 3803KJ

Total energy required to remove Carbon = (9540 + 54240 + 3893) J = 67,673J = 67

7KJ