A solution of methanol, CH3OH, in water is prepared by mixing together 128 g of methanol and 108 g of water. The mole fraction of methanol in the solution is closest to

Mole fraction of methanol = 0.4

Explanation:

Molar mass methanol: 32 g/mol

Molar mass water: 18 g/m

Mol = Mass / Molar mass

128 g / 32 g/m = 4 moles of CH₃OH

108 g / 18 g/m = 6 moles of H₂O

Mole fraction of methanol = Moles of methanol / Moles of methanol + Moles of H₂O

4 / 10 = 0.4