A solution of methanol, CH3OH, in water is prepared by mixing together 128 g of methanol and 108 g of water. The mole fraction of methanol in the solution is closest to

Question

Chemistry

Areli Mata

27 January, 13:16

A solution of methanol, CH3OH, in water is prepared by mixing together 128 g of methanol and 108 g of water. The mole fraction of methanol in the solution is closest to

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Answers (1)

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Vicente Dorsey · Answer 1

Mole fraction of methanol = 0.4

Explanation:

Molar mass methanol: 32 g/mol

Molar mass water: 18 g/m

Mol = Mass / Molar mass

128 g / 32 g/m = 4 moles of CH₃OH

108 g / 18 g/m = 6 moles of H₂O

Mole fraction of methanol = Moles of methanol / Moles of methanol + Moles of H₂O

4 / 10 = 0.4