Ask Question
24 November, 21:59

Suppose the half-life is 35.5 s for a first order reaction and the reactant concentration is 0.0700 M 28.6 s after the reaction starts. How many seconds after the start of the reaction does it take for the reactant concentration to decrease to 0.0063 M?

+5
Answers (1)
  1. 25 November, 00:00
    0
    It takes 151.9 s for the reactant concentration to decrease to 0.0063 M

    Explanation:

    k = ln2 / t1/2

    k = ln2 / 35.5 s = 0.0195 s^-1

    ln [A]t = - kt + ln [A]o

    ln (0.0063) = - 0.0195t + ln (0.0700)

    t = 123.32 s

    Since t is counted from 28.6 s as the initial time, the time after start of reaction to reach 0.0063 M is

    28.6 + 123.32 s = 151.9 s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Suppose the half-life is 35.5 s for a first order reaction and the reactant concentration is 0.0700 M 28.6 s after the reaction starts. How ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers