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16 August, 04:56

Barium and nitrogen form two binary compounds containing 90.745% and 93.634% barium, respectively. Determine the empirical formulas of these two compounds.

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  1. 16 August, 08:04
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    BaN, Ba₃N₂

    Explanation:

    In order to determine the empirical formula of a compound, we have to follow a series of steps.

    Step 1: Determine the percent composition

    Step 2: Divide each percentage by the atomic mass of each element

    Step 3: Divide all numbers by the smallest one

    Step 4: If necessary, multiply by a number so the coefficients are whole

    Compound 1

    Step 1

    Ba: 90.745%

    N: 100% - 90.745% = 9.255%

    Step 2

    Ba: 90.745/137.33 = 0.66078

    N: 9.255/14.01 = 0.6606

    Step 3

    Ba: 0.66078/0.6606 ≈ 1

    N: 0.6606/0.6606 = 1

    The empirical formula is BaN.

    Compound 2

    Step 1

    Ba: 93.634%

    N: 100% - 93.634% = 6.366%

    Step 2

    Ba: 93.634/137.33 = 0.68182

    N: 6.366/14.01 = 0.4544

    Step 3

    Ba: 0.68182/0.4544 = 1.5

    N: 0.4544/0.4544 = 1

    Step 4

    Ba: 1.5 * 2 = 3

    N: 1 * 2 = 2

    The empirical formula is Ba₃N₂.
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