You are given 96g of N2H4 and 92g of N2O4. How many grams of N2 will this reaction produce?

84 grams of N2 will be produced in this reaction.

Explanation:

Molecular weight of N2H4 = 14*2 + 4 = 32

Molecular weight of N2O4 = 14*2 + 16*4

= 28 + 64

= 92

moles of N2O4 = 92 / 92 = 1.0

moles of N2H4 = 96 / 32 = 3.0

N2O4 is the limiting reactant (1.0 moles) so 3 moles of N2 will be produced.

14*2*3 = 84 grams.