Balance the following oxidation-reduction reaction: Fe (s) + Na + (aq) →Fe2 + (aq) + Na (s) Express the coefficients as integers separated by commas (e. g., 4,1,3,2, where 1 indicates the absence of a coefficient).

The answer to your question is: 1, 2, 1, 2

Explanation:

1 Fe (s) + 2 Na⁺ (aq) → 1 Fe²⁺ (aq) + 2 Na (s)

Fe⁰ - 2e⁻ ⇒ Fe⁺² Oxidases

Na⁺ + 1 e⁻ ⇒ Na⁰ Reduces

1 x (1 Fe⁰ ⇒ 1 Fe⁺²) Interchange number of

2 x (2Na⁺ ⇒ 2 Na⁰) electrons