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20 October, 15:56

1) According to the balanced chemical equation below; how many atoms of silver (Ag) will be produced from 100 g of copper (Cu) with excess silver nitrate (AgNO3) ? Cu + 2 AgNO3 ⇒ Cu (NO3) 2 + 2 Ag

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  1. 20 October, 17:30
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    There will be produced 1.89x10²⁴ atoms of Ag

    Explanation:

    This is the reaction:

    Cu + 2 AgNO₃ ⇒ Cu (NO₃) ₂ + 2 Ag

    1 mol of copper reacts with 2 moles of silver nitrate to produce solid silver and 1 mol of copper nitrate.

    Ratio is 1:2 so from the moles I have of Cu, I'll produce the double of moles of silver.

    100 g / 63.55 g / m = 1.57 moles of Cu

    1.57 moles of Cu will produce 3.14 moles of Ag.

    Let's calculate the number of atoms, by NA

    1 mol of Ag has NA atoms (6.02x10²³)

    3.14 moles of Ag will have (3.14. NA) = 1.89x10²⁴ atoms of Ag
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