In What volume will 1.5 moles of oxygen gas occupy at STP?

!

22.4L

033.6L

09.02

20.0L

12

V = 33.62 L

Explanation:

Given dа ta:

Volume = ?

Number of moles of oxygen = 1.5 mol

Temperature = 273 K

Pressure = 1 atm

Solution:

Standard pressure = 1 atm

Standard temperature = 273 K

PV = nRT

V = nRT / P

V = 1.5 mol * 0.0821 atm. L. K⁻¹. mol⁻¹ * 273 k / 1 atm

V = 33.62 L. atm/ / 1 atm

V = 33.62 L