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4 July, 06:28

How much work is required to lift a 0.500 kg block 18.5 m?

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  1. 4 July, 09:21
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    Work = 90.65 j

    Explanation:

    Given dа ta:

    Mass = 0.500 Kg

    Distance = 18.5 m

    Work done = ?

    Solution:

    Work = force. distance

    Force = mg

    Work = mg. distance

    Work = mgh

    Work = 0.500 Kg * 9.8 m/s² * 18.5 m

    Work = 90.65 Kg. m²/s²

    Kg. m²/s² = j

    Work = 90.65 j
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