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25 November, 07:43

a sample of an unkown metal has a mass of 120.7g. As the sample cools from 90.5C to 25.7C, it releases 7020J of energy. What is the specific heat of the sample

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  1. 25 November, 08:51
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    Specific heat of metal = 0.9 j/g.°C

    Explanation:

    Given dа ta:

    Mass of metal = 120.7 g

    Initial temperature of sample = 90.5°C

    Final temperature of sample = 25.7 °C

    Heat released = 7030 J

    Specific heat of metal = ?

    Solution:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = final temperature - initial temperature

    ΔT = 25.7 °C - 90.5 °C

    ΔT = - 64.8°C

    Now we will put the values in formula.

    Q = m. c. ΔT

    7020 J = 120.7 g * c * - 64.8°C

    7020 J = 7821.36 g.°C * c

    c = 7020 J / 7821.36 g.°C

    c = 0.9 j/g.°C
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