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28 August, 19:40

Calculate the percent by mass of a solution containing 0.21 moles of C12H22O11 (gram-molecular mass = 342 g/mole) in 250 g of water.

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  1. 28 August, 19:51
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    28.728%

    Explanation:

    We are given;

    Moles of the solute, C12H22O11 = 0.21 moles

    Molar mass of C₁₂H₂₂O₁₁ = 342 g/mol

    Mass of the solvent water = 250 g

    We need to calculate the percent by mass of a solution

    Step 1: Calculate the mass of the solute

    Mass = Number of moles * Molar mass

    Therefore;

    Mass of solute = 0.21 moles * 342 g/mol

    = 71.82 g

    Step 2: Calculate the percent by mass of the solution

    % by mass = (Mass of solute : mass of the solution) * 100

    = (71.82 g : 250 g) * 100

    = 28.728%

    Therefore, the percent by mass of the solution is 28.728%
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