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23 August, 19:41

A certain first-order reaction (A→products) has a rate constant of 9.00*10-3 s-1 at 45 ∘C. How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration?

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  1. 23 August, 20:04
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    27.8 minutes

    Explanation:

    The reaction follows a first order

    Rate = k[A] = change in concentration/time

    k = 9*10^-3s^-1

    Let the original concentration of A be y

    Concentration of A at time t = 6.25% * y = 0.0625y

    Change in concentration = y - 0.0625y = 0.9375y

    0.009 * 0.0625y = 0.9375y/t

    t = 0.9375y/0.0005625y = 1666.7sec = 1666.7/60 = 27.8 minutes
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