An aqueous solution of sucrose (C12H22O11) is prepared by dissolving 6.4475 g in sufficient deionized water to form a 100.00 mL solution. Calculate the molarity of the solution.

0.1988 M

Explanation:

Molarity of a solution can be defined as the number of moles of solute present in that solution per volume of the solution in liter. Mathematically, molarity can be expressed as:

number of moles/volume (liter)

Also, moles = mass of substance/molar mass

mass of sucrose = 6.4475 g

molar mass of sucrose = 324.3 g/mol

moles of sucrose = 6.4475/324.3 = 0.0199

volume of solution = 100.00 ml = 0.1 liter

Hence, molarity of the solution = 0.0199/0.1

= 0.1988 M

The molarity of the solution is 0.1988 M.