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8 January, 00:24

1f 3.8 kcal is released by combustion of each gram of

glucose, how many kilocalories are released by the

combustion of 1.50 mol of glucose?

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Answers (1)
  1. 8 January, 03:53
    0
    1026.88 kilocalories are released by the combustion of 1.50 mol of glucose

    Explanation:

    First we have to calculate the amount in grams in 1.5 moles of glucose by using formula

    Molecular mass of glucose is 180.156 g/mol

    Mass in grams = Molarity x Molecular mass

    =1.50 moles x 180.156 g/mol

    = 270.23 g

    Now we will calculate the amount of energy released

    Energy released by 1 gram of glucose = 3.8 Kcal

    Energy released by 270.23 gram of glucose = 3.8 x 270.23 Kcal

    = 1026.88 Kcal

    1026.88 kilocalories are released by the combustion of 1.50 mol of glucose
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