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7 May, 01:09

what is the excess reactant for the following balanced equation when 13 moles of ALF3 are mixed with 9 moles of O2

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  1. 7 May, 01:45
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    AlF₃ is the excess reactant

    Explanation:

    We are given;

    13 moles of AlF₃ 9 moles of O₂

    We are required to identify the excess reactant;

    First; we write a balanced equation for the reaction between O₂ and AlF₃

    O₂ and AlF₃ reacts to form Al₂O₃ and F₂ Therefore; the equation of the reaction is

    4AlF₃ + 3O₂ → 2Al₂O₃ + 6F₂

    Second, determine the mole ratio of AlF₃ to O₂

    From the equation 4 moles of AlF₃ reacts with 3 moles of O₂ Therefore; the mole ratio of AlF₃ to O₂ is 4 : 3

    Third; we determine the excess reactant.

    From the mole ration, 13 moles of AlF₃ will require 9.75 moles (13*3/4) of O₂ but only 9 moles of oxygen are available. On the other hand, 9 moles of oxygen would require 12 moles (9*4/3) AlF₃. But we have 13 moles of AlF₃, which means AlF₃ is in excess.

    Therefore; Oxygen gas is the rate limiting reactant and AlF₃ is the excess reactant (1 mole excess).
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