A pure titanium cube has an edge length of 2.64 in. How many titanium atoms does it contain? Titanium has a density of 4.50g/cm3.

1.71 * 10²⁵ atoms

Explanation:

A pure titanium cube has an edge length of 2.64 in. In centimeters,

2.64 in * (2.54 cm / 1 in) = 6.71 cm

The volume of the cube is:

V = (length) ³ = (6.71 cm) ³ = 302 cm³

Titanium has a density of 4.50 g/cm³. The mass corresponding to 302 cm³ is:

302 cm³ * 4.50 g/cm³ = 1.36 * 10³ g

The molar mass of titanium is 47.87 g/mol. The moles corresponding to 1.36 * 10³ g are:

1.36 * 10³ g * (1 mol/47.87 g) = 28.4 mol

1 mol of Ti contains 6.02 * 10²³ atoms of Ti (Avogadro's number). The atoms in 28.4 moles are:

28.4 mol * (6.02 * 10²³ atoms/1 mol) = 1.71 * 10²⁵ atoms