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16 January, 23:13

The value of the solubility product constant for Ag2CO3 is 8.5 * 10-12 and that of Ag2CrO4 is 1.1 * 10-12. From this data, what is the value of Kc for the reaction, Ag2CO3 (s) + CrO42 - (aq) → Ag2CrO4 (s) + CO32 - (aq)

A) 9.6 * 10-12

B) 7.7

C) 1.1 * 1023

D) 1.3 * 10-1

E) 9.4 * 10-24

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Answers (1)
  1. 17 January, 02:21
    0
    B) 7.7

    Explanation:

    For the reaction Ag2CO3 (s) + CrO42 - (aq) → Ag2CrO4 (s) + CO32 - (aq)

    Kc = (CO₃²⁻) / (CrO₄²⁻)

    and the Ksp given are

    Ag₂CO₃ ⇒ 2 Ag⁺ (aq) + CO₃²⁻ (aq) Ksp₁ = (Ag⁺) ² (CO₃²⁻)

    Ag₂CrO₄ ⇒ 2 Ag⁺ (aq) + CrO₄²⁻ (aq) Ksp₂ = (Ag⁺) ² (CrO₄²⁻)

    Where ( ...) indicate concentrations M

    Notice if we divide the expressions for Ksp we get:

    Ksp₁/Ksp₂ = (CO₃²⁻) / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7

    which is the desired answer.
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