Ask Question
17 September, 16:14

Consider the following reversible reaction l. 2H2Og 2H2g+O2g what is the equilibrium constant expression for the given system?

+2
Answers (1)
  1. 17 September, 18:49
    0
    The equilibrium consntant expression is:

    Keq = (02) x (H2) ^2 / (H20) ^2

    Explanation:

    The equilibrium constant is calculated as the ratio between products and reagents raised to their stoichiometric coefficients. In this case, Water (H20) is a reagent and the respective products are Hydrogen (H2) and Oxygen (02)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider the following reversible reaction l. 2H2Og 2H2g+O2g what is the equilibrium constant expression for the given system? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers