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5 October, 16:39

Which of the following is the final concentration of KCl if 500 ml of 0.25 M KCl is diluted to a final volume of 5 L?

0.025 L

0.0025 L

25 L

2.5 L

+5
Answers (1)
  1. 5 October, 18:04
    0
    0.025 M

    Explanation:

    Given dа ta:

    Initial volume = 500 mL (0.5 L)

    Initial molarity = 0.25 M

    Final volume = 5L

    Final molarity = ?

    Solution:

    M₁V₁ = M₂V₂

    M₁ = Initial molarity

    V₁ = Initial volume

    M₂ = Final molarity

    V₂ = Final volume

    Now we will put the values in formula.

    M₁V₁ = M₂V₂

    0.25 M * 0.5 L = M₂ * 5 L

    0.125 M. L = M₂ * 5 L

    M₂ = 0.125 M. L / 5L

    M₂ = 0.025 M
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