The standard heat of formation for CdO (s) is - 258 kJ/mol at 298 K. Write the formation equation for CdO (s) that goes with this value of ΔH°. Use the pull-down boxes to specify states. Write fractions with a slash, such as 1/2 for one half. If a box is not needed leave it blank.

Question

Chemistry

Frisco

25 July, 16:50

The standard heat of formation for CdO (s) is - 258 kJ/mol at 298 K. Write the formation equation for CdO (s) that goes with this value of ΔH°. Use the pull-down boxes to specify states. Write fractions with a slash, such as 1/2 for one half. If a box is not needed leave it blank.

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Sidney Gilmore · Answer 1

Cd (s) + 1/2 O₂ (g) ⇒ CdO (s) ΔH° = - 258 kJ/mol

Explanation:

The standard heat of formation corresponds to the reaction of synthesis of 1 mole of the desired product from the simple substances in their most stable form under standard conditions (1 bar, 25°C). The resulting thermochemical equation is:

Cd (s) + 1/2 O₂ (g) ⇒ CdO (s) ΔH° = - 258 kJ/mol