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6 January, 18:17

The specific heat capacity of water is 4.18 J K⁻¹ g⁻¹. What is the enthalpy (heat) change when 10.00 g of water is heated from 285.0 to 300.0 K (Hint temperature change is the same in °C or Kelvin) ?

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  1. 6 January, 19:13
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    Answer:627j

    Explanation:

    H=mcΔT

    ΔH = 10*4.18 * (300-285)

    ΔH=10*4.18*15

    ΔH=627j
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