Ask Question
20 June, 07:29

Consider the neutralization reaction 2 HNO 3 (aq) + Ba (OH) 2 (aq) ⟶ 2 H 2 O (l) + Ba (NO 3) 2 (aq) A 0.120 L sample of an unknown HNO 3 solution required 45.1 mL of 0.200 M Ba (OH) 2 for complete neutralization. What is the concentration of the HNO 3 solution?

+4
Answers (1)
  1. 20 June, 10:02
    0
    The concentration of the HNO3 solution is 0.150 M

    Explanation:

    Step 1: Data given

    Volume of the unknown HNO3 sample = 0.120 L

    Volume of the 0.200 M Ba (OH) 2 = 45.1 mL

    Step 2: The balanced equation

    2HNO3 + Ba (OH) 2 ⟶ Ba (NO3) 2 + 2H2O

    Step 3: Calculate moles Ba (OH) 2

    moles Ba (OH) 2 = molarity * volume

    moles Ba (OH) 2 = 0.200 M * 0.0451 L

    moles Ba (OH) 2 = 0.00902 moles

    Step 4: Calculate moles of HNO3

    For 1 mole of Ba (OH) 2 we need 2 moles of HNO3

    For 0.00902 moles of Ba (OH) 2 we need 2*0.00902 = 0.01804 moles

    Step 5: Calculate molarity of HNO3

    molarity = moles / volume

    molarity = 0.01804 / 0.120 L

    Molarity = 0.150 M HNO3

    The concentration of the HNO3 solution is 0.150 M
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider the neutralization reaction 2 HNO 3 (aq) + Ba (OH) 2 (aq) ⟶ 2 H 2 O (l) + Ba (NO 3) 2 (aq) A 0.120 L sample of an unknown HNO 3 ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers