Ask Question
10 September, 13:38

For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity, v (as a percentage of Vmax), observed at:a) S=Kmb) S = 0.5 Kmc) S = 0.1 Kmd) S = 2 Kme) S = 10 Km

+1
Answers (1)
  1. 10 September, 15:15
    0
    a) 50% of the maximum velocity

    b) 33.33% of the maximum velocity

    c) 9.09% of the maximum velocity

    d) 66.66% of the maximum velocity

    e) 90.9% of the maximum velocity

    Explanation:

    The Michaelis-Menten kinetis is represented by

    v = Vmax*S / (Km+S)

    where

    v = reaction rate

    S = Substrate's concentration

    Vmax = maximum rate of reaction

    Km = constant

    a) for S=Km

    v = Vmax*Km / (2Km) = Vmax/2

    v/Vmax = 1/2 = 50% of the maximum velocity

    b) for S=Km/2

    v = Vmax * (Km/2) / (3/2Km) = Vmax/3

    v/Vmax = 1/3 = 33.33% of the maximum velocity

    c) for S = 0.1*Km=Km/10

    v = Vmax * (Km/10) / (11/10Km) = Vmax/11

    v/Vmax = 1/11 = 9.09% of the maximum velocity

    d) for S=2*Km

    v = Vmax * (2*Km) / (3*Km) = (2/3) * Vmax

    v/Vmax = 2/3 = 66.66% of the maximum velocity

    d) for S=10*Km

    v = Vmax * (10*Km) / (11*Km) = (10/11) * Vmax

    v/Vmax = 10/11 = 90.9 % of the maximum velocity
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity, v (as a percentage of Vmax), observed at:a) S=Kmb) S ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers