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12 November, 17:00

What volume of nitrogen gas is produced by the explosion of 65.0 g of sodium azide at STP? The balanced chemical equation is 2 NaN3 (s) = 2 Na (s) + 3 N2 (g) for this reaction.

a. 33.6 L

b. 67.2 L

c. No right choice.

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Answers (1)
  1. 12 November, 17:40
    0
    a) V = 33.6 L

    Explanation:

    Given dа ta:

    Mass of sodium azide = 65 g

    Volume of Nitrogen = ?

    Solution:

    Chemical equation:

    2NaN₃ → 3N₂ + 2Na

    Number of moles of NaN₃:

    Number of moles of NaN₃ = Mass / molar mass

    Number of moles of NaN₃ = 65 g / 65 g/mol

    Number of moles of NaN₃ = 1 mol

    Now we will compare the moles of NaN₃ with N₂.

    NaN₃ : N₂

    2 : 3

    1 : 3/2 = 1.5 mol

    Volume of nitrogen gas:

    PV = nRT

    V = nRT / P

    V = 1.5 mol. 0.0821 atm. L. mol⁻¹. K⁻¹ * 273.15 K / 1 atm

    V = 33.64 L
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