Calculate the vapor pressure of a solution prepared by dissolving 0.500 mol of a non-volatile solute in 275 g of hexane (C6H14, MM = 86.18 g/mol) at 49.6°C. P° (hexane) = 400.0 torr at 49.6°C.

Question

Chemistry

Dante Francis

6 August, 22:29

Calculate the vapor pressure of a solution prepared by dissolving 0.500 mol of a non-volatile solute in 275 g of hexane (C6H14, MM = 86.18 g/mol) at 49.6°C. P° (hexane) = 400.0 torr at 49.6°C.

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Answers (1)

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Brylee Tyler · Answer 1

The vapor pressure = 345.8 torr

Explanation:

Step 1: Data given

Number of molesof a non-volatile solute = 0.500 moles

mass of hexane = 275 grams

Molar mass of hexane = 86.18 g/mol

Temperature = 49.6 °C

P° (hexane) = 400.0 torr at 49.6°C.

Step 2: Calculate moles solvent

moles of solvent = 275 grams / 86.18 g/mol = 3.19 mol

Mol fraction of the solvent = 3.19 moles / (0.500 + 3.19) = 0.8645

Step 3: Calculate the vapor pressure

P = P° * Xsolvent

⇒ with Xsolvent = mol fraction of the solvent = 0.8645

⇒ with P° hexane = 400.0 torr

P = 400.0 * 0.8645 = 345.8 torr

The vapor pressure = 345.8 torr