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8 July, 21:47

Balance

NaHCO3 (s) - -> Na2CO3 (s) + H2O (g) + CO2 (g)

Determine how much baking soda you will need to start with in order to produce 2.50 g of sodium carbonate

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  1. 9 July, 00:33
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    Mass = 3.36 g

    Explanation:

    Given dа ta:

    Mass of sodium carbonate produced = 2.50 g

    Mass of baking soda required = ?

    Solution:

    Chemical equation:

    2NaHCO₃ → Na₂CO₃ + H₂O + CO₂

    Number of moles of sodium carbonate:

    Number of moles = mass / molar mass

    Number of moles = 2.50 g / 106 g/mol

    Number of moles = 0.02 mol

    Now we will compare the moles of sodium carbonate and baking soda.

    Na₂CO₃ : NaHCO₃

    1 : 2

    0.02 : 2*0.02 = 0.04 mol

    Mass of baking soda:

    Mass = number of moles * molar mass

    Mass = 0.04 mol * 84 g/mol

    Mass = 3.36 g
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