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22 May, 15:35

You have a mixture of the noble gases Xe, Ne, and He at 6.0 atm. The partial pressure of Xe is 2.7 atm and the mole fraction of Ne is 0.2500. What is the partial pressure of He in this mixture?

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  1. 22 May, 16:18
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    The partial pressure of He = 1.8 atm

    Explanation:

    Step 1: Data given

    The total mass = 6.0 atm

    Partial pressure of Xe = 2.7 atm

    Mol fraction of Ne = 0.2500

    Step 2: Calculate partial pressure of Ne

    Partial pressure Ne = total pressure * mol fraction

    Partial pressure Ne = 6.0 atm * 0.2500

    Partial pressure Ne = 1.5 atm

    Step 3: Calculate the partial pressure of He

    Total pressure = partial pressure of Xe + partial pressure of Ne + partial pressure of He

    6.0 atm = 2.7 atm + 1.5 atm + pHe

    pHe = 6.0 - 2.7 - 1.5

    pHe = 1.8 atm

    The partial pressure of He = 1.8 atm
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