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28 September, 03:46

You need to make an aqueous solution of 0.207 M calcium acetate for an experiment in lab, using a 300 mL volumetric flask. How much solid calcium acetate should you add?

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  1. 28 September, 07:40
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    We have to add 9.82 grams of calcium acetate

    Explanation:

    Step 1: Data given

    Molarity of the calcium acetate solution = 0.207 M

    Volume = 300 mL = 0.300 L

    Molar mass calcium acetate = 158.17 g/mol

    Step 2: Calculate moles calcium acetate

    Moles calcium acetate = molarity * volume

    Moles calcium acetate = 0.207 M * 0.300 L

    Moles calcium acetate = 0.0621 moles

    Step 3: Calculate mass calcium acetate

    Mass calcium acetate = moles * molar mass

    Mass calcium acetate = 0.0621 moles * 158.17 g/mol

    Mass calcium acetate = 9.82 grams

    We have to add 9.82 grams of calcium acetate
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