What is the specific heat (J/g°C) of a metal object whose temperature increases by 3.0°C when 17.5 g of metal was heated with 38.5 J? a. 0.73 b. 0.15 c. 1.4 d. 4.18 e. none of the above

Question

Chemistry

Honey Pie

21 October, 14:38

What is the specific heat (J/g°C) of a metal object whose temperature increases by 3.0°C when 17.5 g of metal was heated with 38.5 J? a. 0.73 b. 0.15 c. 1.4 d. 4.18 e. none of the above

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Answers (1)

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Gay · Answer 1

a. 0.73

Explanation:

Given data

Added heat (Q) : 38.5 J Change in the temperature (ΔT) : 3.0°C Mass of the metal (m) : 17.5 g Specific heat of the metal (c) : ?

We can determine the specific heat of the metal using the following expression.

Q = c * m * ΔT

c = Q / m * ΔT

c = 38.5 J / 17.5 g * 3.0°C

c = 0.73 J/g.°C