What is the concentration of NO3 - ions in a solution prepared by dissolving 30 g of Ca (NO3) 2 in enough water to produce 300. mL of solution. a. 0.305 M b. 0.609 M c. 0.806 M d. None of these

d. None of these

Explanation:

The molar mass of Ca (NO₃) ₂ is 164.088 g/mol. The moles corresponding to 30 g are:

30 g * (1 mol/164.088 g) = 0.183 mol

There are 2 moles of NO₃⁻ in 1 mole of Ca (NO₃) ₂. The moles of NO₃⁻ in 0.183 moles of Ca (NO₃) ₂ are 2 * 0.183 mol = 0.366 mol

The molar concentration of NO₃⁻ is:

0.366 mol/0.300 L = 1.22 M