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1 September, 03:44

How many atoms are in 52.3 g of lithium hypochlorite (LiClO) ?

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  1. 1 September, 05:42
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    1.62 * 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

    Explanation:

    To find the amount of atoms that are in 52.3 g of lithium hypochlorite, we must first find the amount of moles. We do this by dividing by the molar mass of lithium hypochlorite.

    52.3 g : 58.4 g/mol = 0.896 mol

    Next we must find the amount of formula units, we do this be multiplying by Avagadro's number.

    0.896 mol * 6.02 * 10²³ = 5.39 * 10²³ f. u.

    Now to get the amount of atoms we can multiply the amount of formula units by the amout of atoms in one formula unit.

    5.39 * 10²³ f. u. * 3 atom/f. u. = 1.62 * 10²⁴ atoms

    1.62 * 10²⁴ atoms are in 52.3 g of lithium hypochlorite.
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