How many milliliters of ammonium sulfate solution having a concentration of 0.218 M are needed to react completely with 62.6 ml of 2.31 M sodium hydroxide solution?

330 mL of (NH₄) ₂SO₄ are needed

Explanation:

First of all, we determine the reaction:

(NH₄) ₂SO₄ + 2NaOH → 2NH₃ + 2H₂O + Na₂SO₄

We determine the moles of base:

(First, we convert the volume from mL to L) → 62.6 mL. 1L/1000 mL = 0.0626L

Molarity. volume (L) = 2.31 mol/L. 0.0626 L = 0.144 moles

Ratio is 2:1. Therefore we make a rule of three:

2 moles of hydroxide react with 1 mol of sulfate

Then, 0.144 moles of NaOH must react with (0.144.1) / 2 = 0.072 moles

If we want to determine the volume → Moles / Molarity

0.072 mol / 0.218 mol/L = 0.330 L

We convert from L to mL → 0.330L. 1000 mL/1L = 330 mL