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31 August, 19:27

A sample of oxygen occupies a volume of 160dm3 at 91 degrees Celsius. what will be the volume of the oxygen when the temperature drops to 0.00 degrees Celsius

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  1. 31 August, 19:41
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    V₂ = 120 dm³

    Explanation:

    Given dа ta:

    Volume of oxygen = 160 dm³

    Initial temperature = 91 °C

    Final volume = ?

    Final temperature = 0 °C

    Solution:

    First of all we will convert the temperature into kelvin.

    91 + 273 = 364 k

    0 + 273 = 273 K

    According to Charle's law,

    V₁/T₁ = V₂/T₂

    V₂ = V₁T₂/T₁

    V₂ = 160 dm³ * 273 k / 364 k

    V₂ = 43680 dm³. K / 364 k

    V₂ = 120 dm³
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