Consider the reaction, 2 D (g) + 3 E (g) + F (g) = > 2 G (g) + H (g) When D is decreasing at 0.15 mol/Ls, how quickly is E decreasing? Give your answer to 3 decimal places.

Question

Chemistry

London Webster

9 May, 13:40

Consider the reaction, 2 D (g) + 3 E (g) + F (g) = > 2 G (g) + H (g) When D is decreasing at 0.15 mol/Ls, how quickly is E decreasing? Give your answer to 3 decimal places.

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0.023 mol / (L*s).

Explanation:

Equation of the reaction:

2 D (g) + 3 E (g) + F (g) = > 2 G (g) + H (g)

Using stoichiometry, 2 moles of D reacts with 3 moles of E and 1 mole of F to give the above products.

1 mole of D will react with 3/2 moles of E.

Delta[D]/delta t = 0.15 mol/L. s

Delta[E]/delta t = (3/2) * 0.15 =

= 0.023 mol / (L*s).