For the following reaction, 2 SO2 (g) + O: (g) 2 SO, (g) the equilibrium constant, K, is 1.32 at 627°C. What is the equilibrium constant for the reaction below? SO; (g) + 1/2 O: (g) SO, (g)

1.15

Explanation:

2SO₂ + O₂ ⟶ 2SO₃; K = 1.32

SO₂ + ½O₂ ⟶ SO₃; K₁ = ?

When you divide an equation by 2, you take the square root of its equilibrium constant.

K₁ = √1.32 = 1.15

The equilibrium constant is 1.15.