In the reaction of Zn with HCI, 140.15 g of ZnCl2 was actually formed, although the theoretical yield

was 143 g. What was the percent yield?

Question

Chemistry

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16 July, 20:12

In the reaction of Zn with HCI, 140.15 g of ZnCl2 was actually formed, although the theoretical yield

was 143 g. What was the percent yield?

+2

Answers (1)

Know the Answer?

Ciara Guerrero · Answer 1

Percent yield of ZnCl₂ = 98 %

Explanation:

Data Given:

Actual yield of ZnCl₂ = 140.15 g

Theoretical yield of ZnCl₂ = 143 g.

percent yield = ?

Solution:

Formula used

Percent yield = Actual yield / Theoretical yield x 100%

Put values in the formula

Percent yield = 140.15 g / 143 g x 100%

Percent yield = 98.007 %

Rounded to significant figure

Percent yield of ZnCl₂ = 98 %

In the reaction of Zn with HCI, 140.15 g of ZnCl2 was actually formed, although the theoretical yieldwas 143 g. What was the percent yield?

In the reaction of Zn with HCI, 140.15 g of ZnCl2 was actually formed, although the theoretical yield

was 143 g. What was the percent yield?