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Yesterday, 16:59

12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper (II) chloride are

obtained. Calculate the theoretical yield and the percent yield.

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Answers (1)
  1. Yesterday, 19:26
    0
    Percent yield = 94.5%

    Theoretical yield = 26.89 g

    Explanation:

    Given dа ta:

    Mass of copper = 12.5 g

    Mass of copper chloride produced = 25.4 g

    Theoretical yield = ?

    Percent yield = ?

    Solution:

    Cu + Cl₂ → CuCl₂

    Number of moles of Copper:

    Number of moles = mass / molar mass

    Number of moles = 12.5 g / 63.55 g/mol

    Number of moles = 0.2 mol

    Now we will compare the moles of copper with copper chloride.

    Cu : CuCl₂

    1 : 1

    0.2 : 0.2

    Theoretical yield:

    Mass of copper chloride:

    Mass = Number of moles * molar mass

    Mass = 0.2 mol * 134.45 g/mol

    Mass = 26.89 g

    Percent yield:

    Percent yield = Actual yield / theoretical yield * 100

    Percent yield = 25.4 g/26.89 g * 100

    Percent yield = 94.5%
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