Ask Question
3 August, 23:37

200. Grams of copper at 15°C are mixed with 200 grams H20 at 60°C. If the final

temperature of the mixture is 42.7oC, what was the mass of the water?

+5
Answers (1)
  1. 3 August, 23:57
    0
    29.467 g

    Explanation:

    From the question;

    Mass of copper is 200 g

    Initial temperature of copper is 15°C

    Mass of water is 200 grams

    Initial temperature of water is 60°C

    Final temperature of the mixture is 42.7 °C

    We are required to calculate the mass of water

    Step 1: Heat absorbed by copper

    Quantity of heat, Q = Mass * specific heat capacity * change in temperature

    Specific heat capacity of copper = 0.385 J/g°C

    Change in temperature, ΔT = 42.7°C - 15°C

    = 27.7° C

    Q = mcΔT

    Q = 200 g * 0.385 J/g°C * 27.7°C

    = 2132.9 Joules

    Step 2: Quantity heat released by water

    Specific heat capacity of water is 4.184 J/g°C

    Change in temperature, ΔT = 42.7°C - 60°C

    = - 17.3 °C

    Assuming the mass of water is m

    Then

    Q = m * 4.184 J/g°C * 17.3 °C

    = 72.3832m joules

    Step 3: Calculating the mass of water

    The heat gained by the copper metal is equal to the heat released by the water.

    Therefore;

    2132.9 Joules = 72.3832m Joules

    m = 2132.9 J : 72.3832 J

    = 29.4668

    = 29.467 g

    Therefore, the mass of water is 29.467 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “200. Grams of copper at 15°C are mixed with 200 grams H20 at 60°C. If the final temperature of the mixture is 42.7oC, what was the mass of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers