Calculate 50g 25.0c to 95.000

O. 897 J / (g. c)

Q = 3139.5 j

Explanation:

Given dа ta:

Mass = 50 g

Initial temperature = 25°C

Final temperature = 95°C

Specific heat capacity = 0.897 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 95°C - 25°C

ΔT = 70°C

Q = m. c. ΔT

Q = 50 g * 0.897 J/g.°C * 70°C

Q = 3139.5 j