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19 November, 07:48

a mixture of 2 moles of Ne gas and 3 moles of Ar gas are kept in a cylinder at 25.0 degress celcious. what is the indivual pressure of each and the total pressure?

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  1. 19 November, 11:33
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    Hey there!

    Assuming the volume of the cylinder is 1 L.

    Given, T=25 = 298K

    As per the Dalton's law, total P = PNe + PAr ... where PNe = partial pressure of Ne and PAr = partial pressure of Ar.

    PV = nRT

    total P = (total moles) * (0.082057 L atm mol-1K-1 * 298) / 1 = 5*0.082057*298 = 122.27 atm.

    PNe = mole fraction of Ne * total P = (2/5) * 122.27 = 48.908 atm

    PAr = mole fraction of Ar * total P = (3/5) * 122.27 = 73.362 atm

    Total pressure is 122.27 atm

    Ne pratial pressure = 48.908 atm

    Ar prtial pressure = 73.362 atm
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