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12 May, 08:27

The atmosphere is about 21% oxygen. At a pressure of 749 torr, what is the partial pressure of O2?

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  1. 12 May, 10:55
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    157.29 Torr

    Explanation:

    This question may be solved by the mole fraction.

    Mole fraction → Moles of gas / Total moles = Partial pressure of gas / Total pressure

    If the atmosphere is about 21% you assume that the mole fraction is 0.21 so:

    0.21 = Partial pressure of gas / Total pressure

    0.21 = Partial pressure of gas / 749 Torr

    Partial pressure of the gas = 749 Torr. 0.21 → 157.29 Torr
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