Ask Question
6 November, 04:46

Consider HA2, the intermediate form of a diprotic acid. Ka for this species is 1024 and Kb is 1028. Nonetheless, the Ka and Kb reac - tions proceed to nearly the same extent when NaHA is dissolved in water. Explain.

+5
Answers (1)
  1. 6 November, 08:12
    0
    1. naoh + h₂o → na⁺ + oh⁻ + h₂o + heat

    2. naoh + hcl → nacl + h₂o

    explanation:

    1. the dissolving of naoh in water is an exothermic reaction resulting a heat. it also causes the dissociation of naoh to its ions (na⁺ and oh⁻).

    so, the balanced equation will be naoh + h₂o → na⁺ + oh⁻ + h₂o + heat.

    2. the reaction between acid and base resulting salt and water. it is considered as a neutralization reaction.

    the reaction between hcl and naoh will give sodium chloride and water and the balanced equation will be naoh + hcl → nacl + h₂o.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider HA2, the intermediate form of a diprotic acid. Ka for this species is 1024 and Kb is 1028. Nonetheless, the Ka and Kb reac - tions ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers