What is the molarity of. 00000093 grams of epinephrine in one liter?

5.076 * 10 ⁻¹² M

Explanation:

molarity of a solution is given as -

Molarity (M) = (w / m) / V (in L)

where,

m = molecular mass,

w = given mass,

V = volume of solution,

From the question,

w = given mass of epinephrine = 0.00000093 g

V = 1 L

Since, the molecular mass of epinephrine = m = 183,204 g/mol

M = ?

In order to determine the molarity of epinephrine, the above formula is used, by putting the respected values,

Molarity (M) = (w / m) / V (in L)

M = (0.00000093 g / 183,204 g/mol) / 1 L

M = 5.076 * 10 ⁻¹² M