What is the solubility of 80 grams of magnesium chloride (MgCl2) dissolved into 150 cm3 of water?

=53.3g/100g water

Explanation:

Solubility = (Mass of solute*100g solvent) / mass of solent.

Mass of solute=80 grams

Mass of solvent=150g (assuming that the density of water is 1g/cm³)

Thus solubility = (80g*100g) / 150g

=53.3g/100g water

Solubility of Magnesium in water at the given temperature is 53.3g/100g

5.6 moldm^-3

Explanation:

Solubility refers to the the amount of solute that can dissolve in 1000cm3 of solution.

Number of moles of MgCl2 = mass / molar mass

Molar mass of MgCl2 = 24 + 2 (35.5) = 95gmol-1

Number of moles = 80g/95gmol-1 = 0.842 moles

If 0.842 moles dissolves in 150cm^3 of water

x moles dissolves in 1000cm^3 of water

x = 0.842*1000/150

x = 5.6 moldm^-3