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3 January, 15:04

How many grams of NH3 can be produced from 2.30 mol of N2 and excess H2.

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  1. 3 January, 16:20
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    78.34 g

    Explanation:

    From the question we are given;

    Moles of Nitrogen gas as 2.3 moles

    we are required to calculate the mass of NH₃ that may be reproduced.

    Step 1: Writing the balanced equation for the reaction

    The Balanced equation for the reaction is;

    N₂ (g) + 3H₂ (g) → 2NH₃ (g)

    Step 2: Calculating the number of moles of NH₃

    From the equation 1 mole of nitrogen gas reacts to produce 2 moles of NH₃

    Therefore, the mole ratio of N₂ to NH₃ is 1 : 2

    Thus, Moles of NH₃ = Moles of N₂ * 2

    = 2.3 moles * 2

    = 4.6 moles

    Step 3: Calculating the mass of ammonia produced

    Mass = Moles * molar mass

    Molar mass of ammonia gas = 17.031 g/mol

    Therefore;

    Mass = 4.6 moles * 17.031 g/mol

    = 78.3426 g

    = 78.34 g

    Thus, the mass of NH₃ produced is 78.34 g
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