A small cubical furnace 50 by 50 by 50 cm on the inside is constructed of fireclay brick [k = 1.04 W/m. degree C] with a wall thickness of 10 cm. The inside of the furnace is maintained at 500 degree C, and the outside is maintained at 50 degree C. Calculate the heat lost through the walls.

Question

Chemistry

Esther Reynolds

26 January, 14:50

A small cubical furnace 50 by 50 by 50 cm on the inside is constructed of fireclay brick [k = 1.04 W/m. degree C] with a wall thickness of 10 cm. The inside of the furnace is maintained at 500 degree C, and the outside is maintained at 50 degree C. Calculate the heat lost through the walls.

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Agustin Galvan · Answer 1

Q=1170J/s = 279.516cal/s

Explanation:

q=-k. (T₀-T₁) / (x₀ - x₁)

q = heat flow density

T = temperature

x = thickness

q = - (1.04 W/m. ºC). (50ºC-500ºC) / (0.1m-0m)

q=4680W/m²=4,68KW/m²

1KW=1000J/s

∴ q = 4680 J/s. m²

q = Q/A

Q=heat fluw

A = surface = 6. (0.5m. 0.5m) = 0.25m²

Q = (4680J/s. m²). (0.25m²)

Q=1170J/s = 279.516cal/s

1J=0.2389cal